Problem
This problem was asked by Google.
Suppose we represent our file system by a string in the following manner:
The string “dir\n\tsubdir1\n\tsubdir2\n\t\tfile.ext” represents:
dir
subdir1
subdir2
file.ext
The directory dir contains an empty sub-directory subdir1 and a sub-directory subdir2 containing a file file.ext.
The string “dir\n\tsubdir1\n\t\tfile1.ext\n\t\tsubsubdir1\n\tsubdir2\n\t\tsubsubdir2\n\t\t\tfile2.ext” represents:
dir
subdir1
file1.ext
subsubdir1
subdir2
subsubdir2
file2.ext
The directory dir contains two sub-directories subdir1 and subdir2. subdir1 contains a file file1.ext and an empty second-level sub-directory subsubdir1. subdir2 contains a second-level sub-directory subsubdir2 containing a file file2.ext.
We are interested in finding the longest (number of characters) absolute path to a file within our file system. For example, in the second example above, the longest absolute path is “dir/subdir2/subsubdir2/file2.ext”, and its length is 32 (not including the double quotes).
Given a string representing the file system in the above format, return the length of the longest absolute path to a file in the abstracted file system. If there is no file in the system, return 0.
Note:
The name of a file contains at least a period and an extension.
The name of a directory or sub-directory will not contain a period.
Solution
- Each time we meet a file, calculate its path
- A file is a name which contains a period
- A new line is met, a new file or a new subdirectory
- TAB means its indent
#include <algorithm>
#include <iostream>
#include <vector>
#include <stack>
#include <string>
using namespace std;
enum class Type {
File = 0,
Folder = 1,
};
struct Path {
string name;
Type type;
int indent;
int length;
Path(Type t, int ind, int len, string n): type(t), indent(ind), length(len), name(n) {}
};
bool contains(const string& s, char c) {
for (char ss: s) {
if (c == ss) return true;
}
return false;
}
int parse(const string& s) {
if (s.empty()) return 0;
int max_size = 0;
vector<Path> st;
int i = 0;
int indent = 0;
int size = s.size();
while (i < size) {
int j = i;
while (j < size && s[j] != '\n') ++j;
string sub = s.substr(i, j - i);
int prev_size = st.empty() ? 0 : st.back().length;
cout << "name: " << sub << " size: " << sub.size() << " indent: " << indent << endl;
if (contains(sub, '.')) {
// a file
cout << "Find a file: " << sub << endl;
for (auto p : st) {
cout << p.name << ":" << p.length << ", ";
}
cout << endl;
max_size = max(max_size, prev_size + (int)sub.size());
} else {
// a subdirectory
while (!st.empty() && st.back().indent >= indent) st.pop_back();
int prev_size = st.empty() ? 0 : st.back().length;
Path p(Type::Folder, indent, prev_size + sub.size() + 1, sub);
cout << "add folder: " << p.length << endl;
st.push_back(p);
}
++j;
indent = 0;
while (j < size && s[j] == '\t') {
++j;
++indent;
}
i = j;
}
return max_size;
}
int main() {
string str = "dir\n\tsubdir1\n\t\tfile1.ext\n\t\tsubsubdir1\n\tsubdir2\n\t\tsubsubdir2\n\t\t\tfile2.ext";
cout << parse(str) << endl;
string str1 = "dir";
cout << parse(str1) << endl;
string str2 = "dir\n\tdir2";
cout << parse(str2) << endl;
return 0;
}